I have been fiddling with an off the shelf 1000W, 48 V, 20 Amp ZVS driver with a 5 mm copper work coil and powered by a MeanWell RSP-1000-48. The medium I'm heating is an iron pipe (due to it's highly ferromagnetic properties).

Tried using litz wire instead of copper coil, but with limited results. However as I understand it a litz wire should be the preferred type of heating "coil". The diameter of copper tube and litz wire coil is identical.

The first testing with the off the shelf ZVS drive I notices quite a heat loss from within the heating coil. Then I completely insulated the iron pipe with an aero gel matting and am now retaining all the heat.

My main question is: If I were to double the size of the ZVS driver to a 2kW, 48V 20 amp and likewise have a 2kW 48V power supply .....would I be able to heat the Iron pipe twice as fast?

 

You would need a 48V 40Amp psu,...

 

@Dodgydave Will it matter whether doubling the amps is done with a power supply of i.e. a Mean Well RSP-2000-48 that has an with an output of:
48V
42A
2016W

or the Mean Well RSP-1000-24
24V
40A
960W

??

(Not taking into account the 2 amps difference of course)

 

If you want 2KW, then you need a psu to comply with that rating...

 

In other words the RSP-2000-48 connected to a 2kW, 48V 40 amp ZVS driver will provide the same energy as the RPS-1000-24 connected to a 1kW, 24V, 40 amp....is that correct?

 

No, 48V x40A = 1920W.

24V x 40A = 960W .

 

Thanks - got it.