http://www.allaboutcircuits.com/textbook/direct-current/chpt-16/voltage-current-calculations/

I am just starting to understand this but the above page shows to methods for calculating the current for the capacitor.
It shows two different methods. And two very different results but comments "Either way we get the same answer".
First answer is 1.4989 mA and second answer is 1.065 microAmps. I dont know if either is correct.

 

On closer look it may be trying to describe two different components and that when summed, they equal the source voltage.

 

The first answer is not 1.4989 mA, but -1.4989 mA. They even make a specific point about it being negative.

This is the amount that the current has changed by relative to the starting current of 1.5 mA in the first 7.5 seconds. So the actual current at t=7.5 seconds is the sum of the two, which leaves you with about 1.1 uA.

I'm not a big fan of their approach, but I do have to give them kudos for, mostly, tracking their units throughout the work. That is pretty rare.