.

 

The data sheet clearly indicates a maximum voltage of 5.5 volts so a 78L05 or similar regulator is required. Those are ubiquitous and inexpensive, don’t risk damage.

 

Hi

I am planning on using a DS32KHZ oscillator module. The supply voltage must be 5 volts for this device.
I want to use it in a circuit that will have a 10 or 15 volt supply and employ CD4000 series chips. If I use
a voltage divider will that work or do I need to use a 5-volt regulator IC for the oscillator supply? I am
concerned about destroying the module as they are pricey little critters.

https://www.analog.com/en/products/ds32khz.html

Thanks

I'd use a suitably biased TL431 as a 5V regulator if I were doing it, but then I have 100's of them! You'll need a level shifter on the output of the module of course!

 

Hi

I am planning on using a DS32KHZ oscillator module. The supply voltage must be 5 volts for this device.
I want to use it in a circuit that will have a 10 or 15 volt supply and employ CD4000 series chips. If I use
a voltage divider will that work or do I need to use a 5-volt regulator IC for the oscillator supply? I am
concerned about destroying the module as they are pricey little critters.

https://www.analog.com/en/products/ds32khz.html

Thanks

A voltage divider should never be used in power applications. It works best in signal applications where the load is high impedance, like an opamp input.

 

Thanks Sarah!

I'd do away with the second transistor circuitry altogether, make the base resistor into the first one much bigger, say 22k, and connect the collector resistor directly to your 10V or 15V CMOS supply. That way you reduce the self heating within the oscillator package.

 

The actual 5 volt regulator is the ONLY way to go, because if you connect it correctly and ad those two 0.1 mfd bypass capacitors you get 5 volts. No selecting a resistor correctly, just get the correct regulator and it is right. AND certainly it will provide a 5 volt signal so certainly you will need a buffer, which has already been mentioned.