You've specified an AC to DC conversion. For a buck-boost converter you need to specify a DC input range. This range will include the output voltage of +12VDC. Then we have 12VDC times 5 Amperes = 60 Watts of output power. At 85% efficiency you'll need 70.6 watts of input power. Let us say your input range will be +4VDC to +18VDC. At +4VDC, 70.6 watts will require 17.64 Amperes. The inductor in your buck boost supply will need to be able to handle twice that current or 35.3 Amperes. At +18VDC things are much better; you'll only need 3.9 Amperes on the input and twice that or 7.8 Amperes in the inductor.I want to make with own specifications. It's for hobby/home use.
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It should have high efficiency (80-90%).
Input: 120V 60Hz and/or 220V 50Hz
Output: 12V, about 4-5A.
Don't waste your time, just buy a ready made one....I want to make with own specifications. It's for hobby/home use.
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It should have high efficiency (80-90%).
Input: 120V 60Hz and/or 220V 50Hz
Output: 12V, about 4-5A.