R7. Why would you place 8.2k in series with the ground for all the circuits?
R1, Why would you place 820 ohms in series with the power supply for the 555 chip (and everything else on the board)?
Why are three resistor hanging off the side with no job to do?
D1. If you're going to cheap out on 7 cent diodes, you have to double the filter capacitor size from (calculated) 150 uf to 300+uf. Ps, using half as many rectifiers doesn't reduce the DC voltage, that only makes the ripple voltage double.
Meanwhile, that 150 uf was calculated only for the receiver. This will need more capacitance to supply the 555 oscillator and the IR emitter. Are you locked in to the NE555? That will give me a solid number for amperage needs.

Meanwhile, the IR receiver has it's current limiter (R8) on the wrong end, there is no frequency limiting circuit between it and the 2N2222.
R6, R7, and R8 limit the current to the opto LED to 1.6 ma when it should be 20 ma. You can't run a triac gate off the base of the opto receiver transistor. You can't use an NPN transistor to control AC (wrong opto-isolator). You need a triac output opto to control a power triac. You can run a power triac gate with DC, but that would mean making a second DC supply with the second transformer winding or forfeiting the isolation feature of the opto-isolator. You have the fuse in the neutral line. C6 and C7 are supposed to be snuggled up against the 555 chip. And a partridge in a pear tree.

This looks like you're trying to make the connectors for the outside world nice and neat, at the expense of everything else looking like a bowl of spaghetti, and the spaghetti is wired wrong in so many ways.

I'm going to combine the transmitter and receiver circuits for you in a new drawing.

 

R7. Why would you place 8.2k in series with the ground for all the circuits?
R1, Why would you place 820 ohms in series with the power supply for the 555 chip (and everything else on the board)?
Why are three resistor hanging off the side with no job to do?
D1. If you're going to cheap out on 7 cent diodes, you have to double the filter capacitor size from (calculated) 150 uf to 300+uf. Ps, using half as many rectifiers doesn't reduce the DC voltage, that only makes the ripple voltage double.
Meanwhile, that 150 uf was calculated only for the receiver. This will need more capacitance to supply the 555 oscillator and the IR emitter. Are you locked in to the NE555? That will give me a solid number for amperage needs.

Meanwhile, the IR receiver has it's current limiter (R8) on the wrong end, there is no frequency limiting circuit between it and the 2N2222.
R6, R7, and R8 limit the current to the opto LED to 1.6 ma when it should be 20 ma. You can't run a triac gate off the base of the opto receiver transistor. You can't use an NPN transistor to control AC (wrong opto-isolator). You need a triac output opto to control a power triac. You can run a power triac gate with DC, but that would mean making a second DC supply with the second transformer winding or forfeiting the isolation feature of the opto-isolator. You have the fuse in the neutral line. C6 and C7 are supposed to be snuggled up against the 555 chip. And a partridge in a pear tree.

This looks like you're trying to make the connectors for the outside world nice and neat, at the expense of everything else looking like a bowl of spaghetti, and the spaghetti is wired wrong in so many ways.

I'm going to combine the transmitter and receiver circuits for you in a new drawing.

I just put this in a word .doc, I'm glad your explaining these to me. I tried to mash all my circuits including my circuit boards layout instead of re-designing all of it. I did install a second diode for a full wave and it increased my voltage to 12vdc? Looking forward to a decent schematic that makes sense. I'll toss out the idea of using my little detector board and design a new one. Their cheap now, not like back in the day.

Thanks again, @#12

kv

 

I'm now seeing a lot of what I did, I'm wiring the Transformer as you did, put in another diode and currently separating LTR and putting in the 555's circuit and trying to follow your post #129

kv

 

Are you locked in to the NE555? That will give me a solid number for amperage needs.

Yes, a 555 will do.

kv

 

Does this float your boat?

 

Looks like connector 2 is numbered backwards.
I don't have a value for the filter cap or the opto triac driver yet.
And I repeat, the number of rectifiers does not change the power supply voltage.
Oh yeah, the fuse size...depends on the motor...unless you want to install a second fuse just for the motor.

 

Yes, a 555 will do.

There are different kinds of 555. Exactly which 555 is important. NE and TL are available. Not much difference for this circuit, but the NE eats more current.

 

TL is fine, second fuse would work. I'll copy this and put it into eagle, once I get all the proper components in the build list I should be able to port the board to the auto layout.

 

I don't know how you're going to stop the fuel feeder from running for the several minutes it takes for new smoke to arrive at the exit, but it's not in this circuit. Maybe hold off on the circuit board for a while?

I'm distracted right now. It will take me some time to get back and re-calculate for the TL555.

 

Does this float your boat?View attachment 116770

I''m going to try and put this into spice, I have a model of a dimmer circuit that I can change some values and run a simulation.

I don't know how you're going to stop the fuel feeder from running for the several minutes it takes for new smoke to arrive at the exit, but it's not in this circuit. Maybe hold off on the circuit board for a while?

I'm distracted right now. It will take me some time to get back and re-calculate for the TL555.

I was thinking a hall effect circuit?

kv

 

Hall effect what? How high the chips are piled in the combustion chamber?

 

I don't know how you're going to stop the fuel feeder from running for the several minutes it takes for new smoke to arrive at the exit, but it's not in this circuit. Maybe hold off on the circuit board for a while?

I'm distracted right now. It will take me some time to get back and re-calculate for the TL555.

I'm watching this exchange closely. I think it is necessary to wait a little after a batch of chips has been fed, and then check if smoke is being produced.

All these conditions and are far easier for me to implement using an MCU. So what I'll do is wait for agreement, especially regarding choosing the appropriate sensor and its modulation. And then I'll build an MCU version of this project. Posting plans, diagrams and code in the end.

 

Hall effect what? How high the chips are piled in the combustion chamber?

Your right, limiting the time before smoke, I just wanted it to stop at one rotation with a hall effect switch on/off. We used them at the Shooting Range Company to sense states.

I don't know?

kv

 

Your right, limiting the time before smoke, I just wanted it to stop at one rotation with a hall effect switch on/off. We used them at the Shooting Range Company to sense states.

I don't know?

kv

Are you planning to feed the chips using a motorized screw drive?

 

I'm watching this exchange closely. I think it is necessary to wait a little after a batch of chips has been fed, and then check if smoke is being produced.

All these conditions and are far easier for me to implement using an MCU. So what I'll do is wait for agreement, especially regarding choosing the appropriate sensor and its modulation. And then I'll build an MCU version of this project. Posting plans, diagrams and code in the end.

I wonder how this could be deployed?

kv

Edit: Delay's up to Ten minutes

 

Are you planning to feed the chips using a motorized screw drive?

Ya, or a rotating drum batch feed.

kv

 

I think I got all the values labeled.
This thing should drive any power triac that fires in quadrant I and quadrant III.

Complete with zero crossing detector in the triac driver.
The output power of the transformer is less than 1 watt, so it's impossible to buy one that is too small.

 

I think I might have a delay circuit using the below 555 delay, 2 Hall Effect Switches and one 555 15 minute delay, 3 magnets.

1. If smoke good.

2. If no smoke need more time.

15 Minute Timer Circuit

15*60 = 1.1*R1*1000 uF

R1 = 818.2 k ohm



Still not sure if I'm there yet.

kv

Edit: Oh, and a pull down transistor.

 

I think I got all the values labeled.
This thing should drive any power triac that fires in quadrant I and quadrant III.
View attachment 116778
Complete with zero crossing detector in the triac driver.
The output power of the transformer is less than 1 watt, so it's impossible to buy one that is too small.

Bread board this then, move to the next step. Delay, Delay, Delay.

kv

 

I personally disagree with the need to warm up the smoking chamber before putting the meat in.
Hot or cold smoker, the meat absorbs the smoke when the meat is cold much better than when it is cooking.
Just put in your meat. Set your thermostat cut off temp. Run the auger with a simple on off (probably a 555) signal controlled with a pot to time the on interval.
Have the smoke stack sensor override the auger timer if temp is under limit set at thermostat.
Have temp limit exceeded signal operate the flue damper.

I re-read this and find @Kermit2 didn't receive credit.

@shortbus Thanks also.

kv