Do you mean your calculations from a few posts back or from the figures I had in my previous post?No quite.
My calculations give a cut off of 14.5V.
Do you mean your calculations from a few posts back or from the figures I had in my previous post?No quite.
My calculations give a cut off of 14.5V.
From you resistor values in post #19.Do you mean your calculations from a few posts back or from the figures I had in my previous post?
Thanks.From you resistor values in post #19.
Here's how I often do divider calculations:
- Their is 500mv across the 9.53kΩ resistor at the cut-off point so its current is 0.5/9.53k = 52.47μA.
- This current also goes through the 267kΩ resistor so its drop must be 52.47μA * 267kΩ = 14.0V.
- The input voltage at the top of the 267kΩ resistor must then be the sum of those two voltages or 14.5V.
OK.Those resistor values give a 14V cutoff.
Is that what you want?
Is that board compatible with the pinout pattern of the surface mount devices you ordered?
Why are is the 10kΩ resistor 0.1% while the 270kΩ resistor is 1%?
They should both be the 0.1% if you are trying to tighten the tolerance of the cutoff voltage.
If you want the voltage to be adjustable you could substitute a 20kΩ trimpot for the 10kΩ resistor.
Otherwise I see no obvious problems with your part's list.
That is correct.I have made a slight change and changed the 10kohm for 9.76k. This should give a 14.3v cutoff if I'm not mistaken
I mean are the solder pad spacings on the SMT board compatible with the pin spacing of the parts you are ordering.Where you say 'is that board compatible...' do you mean my actual power supply unit that I currently have?
Not quite sure what you mean, but it makes no difference which resistor is the 1% and which is the 0.1%, the effect on the cutoff voltage tolerance is the same (1.1% total).Could I possibly juggle these two around bringing one down to maybe get the lower tolerance & raising the other to the limit of 0.1%.
Sorry half asleep posting.That is correct.
I mean are the solder pad spacings on the SMT board compatible with the pin spacing of the parts you are ordering.
Not quite sure what you mean, but it makes no difference which resistor is the 1% and which is the 0.1%, the effect on the cutoff voltage tolerance is the same (1.1% total).
It's just a 2 milliamp limiter for the LED. I don't know why you can't do that with a resistor (because you know what the input voltage is). Mfg. = Central Semiconductor.As for the CLD3, I cannot find this part for sale anywhere, so what would be the equivalent?
It's just a stupid LED with a maximum current of 15 ma. Anything that will physically fit will work.Again, the D3, cannot find this but think I have found similar: http://uk.rs-online.com/web/p/visible-leds/7870051/ma.
Right. 1N4148 is so common my grandmother knew about them. The only thing stalling you is getting parts in surface mount packages.The D4 is not an issue, here: http://uk.rs-online.com/web/p/switching-diodes/7614283/
As per my earlier post, this part was not an issue, I have since change from SMD to through hole version: http://uk.rs-online.com/web/p/products/7003674/Right. 1N4148 is so common my grandmother knew about them. The only thing stalling you is getting parts in surface mount packages.
Again, this I have already sorted, it's just this CLD3 part now.It's just a stupid LED with a maximum current of 15 ma. Anything that will physically fit will work.
Cheers #12, I did look at going the resistor route.Find input voltage, max. Subtract LED voltage. Calculate resistor for 2 ma.
what? about (14V - 2.1V)/0.02?
The price got a lot better since the last time I looked, but they still aren't down to 7 cents, like a resistor.I have now found the CLD3 part: