Thanks, ak. You said it much better than I could, but without taking a deep dive on the opamp datasheets I was unable to get much past my vague hunch.RB is there for bias current cancellation/compensation.
Depending on the circuit and the parts, the input pins to an opamp can either source or sink and very small current. This is the base current needed for the input transistors to function. If the currents into the two pins are not equal, this can cause a DC offset error in the output signal. Sometimes these errors are so low that the designer can choose to ignore them.
The first-order approach to mitigate this error is to make the DC resistance paths for the two inputs to be equal. In this case, make the resistance seen by the inverting input equal to the sum of all of the resistances in series with the non-inverting input. Note that these resistance paths do not have to be to GND; they have to be to a low impedance point, such as the circuit's own output or the output stage of a previous circuit.
The filter topology shown is sometimes called "DC-accurate", meaning the DC operating point of the output is equal to the DC component of the input signal. RB is there to make it more accurate.
ak
I think many of you are missing one salient point, the value of RB is 50% bigger than the DCR on the -ve input. Is it possible that RB also serves as a stability component? RB together with the -ve input terminal capacitance will form a low pass filter and reduce the feedback at higher frequencies as well as introduce a pole somewhere possibly relevant.Dear Team,
The below image is from LTC1966 datasheet.
May I know the use of RB
View attachment 340407