Rewire Ikea Rolfstorp

Externet

Joined Nov 29, 2005
2,635
The integrated circuits shown should have data sheets and application notes to discern how to avoid the touch switch and do it the other way.
 

MisterBill2

Joined Jan 23, 2018
27,577
The PCB has 3 IC packages having 8 leads each. It has a total of at least 61 other components and at least one transistor. So this is not a simple circuit package. While two of the IC packages appear to have numbers the middle one does not appear to have much of a label. In addition, the white solder mask cover makes following conductors rather challenging.
So tracing out much of the circuit will be a serious challenge, even if information is available about the 3 IC devices, which I do not expect it to be available.
I doubt that the TS has the time to trace out the circuit, and who else would spend that much time on it??
,
 
I know this is an old thread, but I have solved this issue so I wanted to share my solution. Hope this helps someone!

There are 3 ICs on the board.

The one closest to the USB connection is a CS32F302, a small MCU from CR Micro (Chineese company), small description available in Chineese here. I have not been able to figure out all of the pin functions, but pin 8 seems to output either a PWM or an analog value, to control the LED driver IC.

The second closest is the LED driver IC. It is a MT7282 from Maxic, small datasheet available here. It is the IC driving the current for the LEDs. Pin 2 is called ADJ, and is used to control the dimming of the LEDs, either using an analog singal or PWM. It is connected to the MCU pin 8 via some resistors and capacitors.

The third IC is a battery charging/control IC. When running only on USB this can be ignored.

Since the workings of the MCU is hard to know, as I do not have the code, I will try and bypass that. By measuring the ADJ pin on the LED driver IC for the various dim levels I can see that at the brightest it seems to be at ~1.6V. To acheive that without the MCU interfering, I removed R43 and R45, and pulled the ADJ pin to 5V via a 20k resistor. With 10k resistor (R58) down to GND still present, I get a voltage division and end up with ~1.6V at the ADJ pin. Thus, making the LEDs turn on as soon as I have 5V, i.e. the USB connected.

Resistors to remove (desolder):

remove.png

Addition of pullup via 20k to 5V:

pullup.png
 
Top