Hi Everybody!
I am currently interning at a company before I return to university for my masters and I am trying to help solve a problem of resistors (sometimes) blowing out on a board when the boards are connected to a power source (physically connected).
Here is what I have figured out so far:
The total power waveform for parallel resistors is shown below (ie. There are two parallel resistors so each experiences half the peak power).

The circuit is shown below as well as some assumption made to simply it are shown below (note, the actual resistors are now 680 Ohm not 220 Ohm):

What I think is happening:
So what seems to be happening is that the 110Vdc to 24Vdc converters input pin is taking time to charge up from 0V to 110V. This means that during startup the equivalent load behaves like a capacitor with negligible inductance and resistance. (see circuit and simplified circuit above). This capacitive load during startup also means there is a voltage pulse of 110V across the resistors which dies down asymptotically. This voltage pulse ofcourse cause a power pulse in the resistors which could potentially damage the resistors (shown first figure).
My questions are:
1) Is the circuit design flawed, leading to the blowout? (The simple low power 1206 resistors seems like a inelegant solution at best)
2) If yes to 1) how can the design be improved?
3) Since the PCB have already been printed, is it possible to replace 1206 package chip R25, R26 and the 2512 package fuze (F1) with other components that may solve the problem?
Some additional info:
110V input can vary between 70V and 150V.
Output power of load is about 1.6W (meaning about 15mA input on the 110V line)
The resistors are 1206 package 0.5W 680 Ohm resistors. So it makes sense that they cannot handle the 50W peak reliably.
I am currently interning at a company before I return to university for my masters and I am trying to help solve a problem of resistors (sometimes) blowing out on a board when the boards are connected to a power source (physically connected).
Here is what I have figured out so far:
The total power waveform for parallel resistors is shown below (ie. There are two parallel resistors so each experiences half the peak power).

The circuit is shown below as well as some assumption made to simply it are shown below (note, the actual resistors are now 680 Ohm not 220 Ohm):

What I think is happening:
So what seems to be happening is that the 110Vdc to 24Vdc converters input pin is taking time to charge up from 0V to 110V. This means that during startup the equivalent load behaves like a capacitor with negligible inductance and resistance. (see circuit and simplified circuit above). This capacitive load during startup also means there is a voltage pulse of 110V across the resistors which dies down asymptotically. This voltage pulse ofcourse cause a power pulse in the resistors which could potentially damage the resistors (shown first figure).
My questions are:
1) Is the circuit design flawed, leading to the blowout? (The simple low power 1206 resistors seems like a inelegant solution at best)
2) If yes to 1) how can the design be improved?
3) Since the PCB have already been printed, is it possible to replace 1206 package chip R25, R26 and the 2512 package fuze (F1) with other components that may solve the problem?
Some additional info:
110V input can vary between 70V and 150V.
Output power of load is about 1.6W (meaning about 15mA input on the 110V line)
The resistors are 1206 package 0.5W 680 Ohm resistors. So it makes sense that they cannot handle the 50W peak reliably.