Hmmmmm..... Well I browsed it and I bookmarked the home website. Looks a good one for hobbyists. Thankyou.
But seriously, all I want to do is build ONE single-output oscillator. Ideas?
Hmmmmm..... Well I browsed it and I bookmarked the home website. Looks a good one for hobbyists. Thankyou.
1 yep I meant inverters1Those are not rectifiers. Those are inverters. A simple logic gate actually is a very high gain linear amplifier acting as a comparator.
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2To learn more with less work, consider building it using sections of a hex inverter or quad NAND gate. Since you don't need a reset pin and are not driving other loads, you need only two inverters to reproduce this oscillator.
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3 Suffice to say that you should use gates with hysteresis, such as the CD4093 or CD40106.
https://en.wikipedia.org/wiki/Hysteresis (after the basics, skip down to "electronic circuits")
https://en.wikipedia.org/wiki/Schmitt_trigger
ak
Mellisa, I strongly suggest you download digital works. It's an excellent way to learn about digital gates and logic, and it's very easy to use. Plus it's free!1 yep I meant inverters
2 pt taken
3 ok sounds good. I wld like to make that the next project - before nuancing the irritation circuit in the manner suggested by dendad and you eg adding a 555 to vary individual relay times - which I still intend to do. But after I learn more abt basic logic gates.
I'll buy some 4093s / 40106s and get to.
I googled it and there's lots of practical literiture for me to draw on .. + u guys!
Eg this relic from antiquity: https://forum.allaboutcircuits.com/...9/?temp_hash=bea0a16322b411504716dbb256816c4a
Ok thx for the advice cmartinez. I will! I'll let I know how I goMellisa, I strongly suggest you download digital works. It's an excellent way to learn about digital gates and logic, and it's very easy to use. Plus it's free!
Excellent article; I still have the original. Note that the oscillator that is the basis for most of the circuits is not the same as the oscillator in the 4060. That one is based on two gates in series, and only the one between pins 11 and 10 would benefit by having hysteresis. Note that the datasheet does not indicate this, although the "2.2" factor in the equation is a strong indication that it is in there. More reading is attached.I googled it and there's lots of practical literiture for me to draw on .. + u guys!
Eg this relic from antiquity: https://forum.allaboutcircuits.com/...9/?temp_hash=bea0a16322b411504716dbb256816c4a
Nice article, but there's an error in Figure 2 B in that the first pulse is shown as being the same width as the subsequent pulses.1 yep I meant inverters
2 pt taken
3 ok sounds good. I wld like to make that the next project - before nuancing the irritation circuit in the manner suggested by dendad and you eg adding a 555 to vary individual relay times - which I still intend to do. But after I learn more abt basic logic gates.
I'll buy some 4093s / 40106s and get to.
I googled it and there's lots of practical literiture for me to draw on .. + u guys!
Eg this relic from antiquity: https://forum.allaboutcircuits.com/...9/?temp_hash=bea0a16322b411504716dbb256816c4a

Is that significant?Nice article, but there's an error in Figure 2 B in that the first pulse is shown as being the same width as the subsequent pulses.
kewlDepends on the application. This is a common "feature" of all relaxation oscillators and many other oscillator types. In your case it is 1/32768th of the first timing cycle. I doubt the plants will notice.
ak
Might or might not be, but it's just intended as a heads-up.Is that significant?
Thankyou for your consideration, E.Might or might not be, but it's just intended as a heads-up.
Hi @cmartinezdownload digital works. It's an excellent way to learn about digital gates and logic, and it's very easy to use. Plus it's free!
hello @dendad hello @AnalogKidI'm not a big fan of large R-C timers, but in this case precision is not required. Here is a first pass at the idea. Note that C1 might have to be increased if its leakage current is a noticeable percentage of the charging current.
http://www.ohmslawcalculator.com/555-astable-calculator
ak
View attachment 126056
I think the datasheet has a common (COM) and ground, No + power. An wouln't you know COM generaly goes to a + voltage, buy it's not needed unless driving relays. So for understanding erase all of the diodes and the COM connection.Pin 10 of ULN2003 stays stuck on 4.8VDC. Will not advance. There is about 1V on the other six output pins. Placement of shunt at P1 makes no difference eve
Thanks for your post @KeepItSimpleStupidBack to post #105.The ULN2003 is a bad chip for newbies to understand.
I think the datasheet has a common (COM) and ground, No + power. An wouln't you know COM generaly goes to a + voltage, buy it's not needed unless driving relays. So for understanding erase all of the diodes and the COM connection.
What your left with are transistors with different base configurations for the ULN200x chips that adapt to various logic families. That said, they exist as open collector drivers where no + is needed for the chip to function, just base current.
Since relays that are driven by transistors need a diode clamp. The inductor stores the voltage because the inductor's current can't change instantaneously briefly when turned off. of the relay coil.
When you put those diodes in place, each output gets he cathode of the diode and the anode goes to the relay supply voltage.
The nice thing about the ULN200x chips is that with the inputs disconnected, the device is OFF. TTL inputs float high when not connected and many processor ports default to an input or high Z state when initially turned on, so the things your trying to control are off at power up until they are correctly configured for an output with a 0 state.
True CMOS inputs should never float. Rule is to make the unused gates use the least amount of power when selecting a 0 or 1 as the input.
There is an 8 channel version of this chip. You have to watch the total power dissipation.
I'm glad this is turning into an education instead of an intimidation. I think I see you are back to digital gates and counters instead of microprocessors. As an old hand at this, and also a bit too old to prefer MPUs, I thought this was a piece of cake on the first page. Now you're at 175 posts? Whew! It really turned into an education! That's good. Most people come here because they don't want to learn. They want the circuit handed to them.I am sooooo glad I chose this sub field of electronics as my first introduction to the broader hobby. I am enjoying it immensely. And its got lots of applications to solve things in my life that I didn't realize existed!!
No offense intended, but "I doubt the plants will notice" sounds to me like snark.Depends on the application. This is a common "feature" of all relaxation oscillators and many other oscillator types. In your case it is 1/32768th of the first timing cycle. I doubt the plants will notice.
ak
Yes. And, I'm stupid. I've been using P0 and P1 for this part for decades, and completely forgot about the Phi marking.
P1, P0-, and P0 are the inputs and outputs of two inverters in series, so the states of those pins always are 1-0-1 or 0-1-0. We'll call the inverters Left and Right.
Start at the moment P0 goes high.
The voltage across a capacitor cannot change instantaneously, so this pulls the timing node (Rx-Cx-Rs) high. This puts a high at P1 (the Left input). It tries to put a high at P0- through Rx, but P0- is held low by the Left output.
This operating state is stable, because two inverters in series forms a latch due to positive feecback: P0 is high, P1 is high, P0- is low, P0 is high.
But while this state is stable, there is a voltage across Rx because the left end of Cx is high but P0- is low. So Cx discharges through Rx into the P0- low output of the Left inverter.
After a time, the voltage at the Rx-Cx-Rx node is low enough that Left input P1 sees it as a logical low, and Left changes state.
P1 is low, P0- goes high, P0 goes low.
Now everything is reversed from where we started, and Cx starts charging in the opposite direction.
Describing an oscillator in text always is difficult, so try to digest this and ask away.
ak
thanks for the invite AK so here goes.. (I am revisiting this bit about the oscillator circuitry of the 4060)..Describing an oscillator in text always is difficult, so try to digest this and ask away.

Our local hospital has a lot of "wave here" type of switches for door openers.e can make a switch work on his own but only with disproportionate difficulty and perserverance. Its an exhausting struggle, occupying a large amount of his attention, time and effort. I dont think it needs to be so difficult for him to turn his things on and off.