Hi,
I am looking to use MP1495S regulator.
As you can see I have 7 ports, I confused by the Vcc port.
What voltage should I connect to it?

In some pages in the data sheet it say 5v and in some GND.
but, if I need to produce 5v by the regulator, how can I supply it too?


I hope I was understandable.
BTW, I am an apprentice in the field, so I will be happy if you have good guides / videos to help me practice in circuit design.
Thank you.

 

It's a little confusing since it's shown as an I/O pin, but Vcc is the internal 5V bias voltage.
It's not an input, so no external voltage is applied.

Use the circuit as shown in the bottom right of your post.

 

You must read and understand the applications information, which describes the operation, not just the connections. The other connections are not all "external input ports."

 

Why are You using a Regulator with a bunch of extra features that You don't understand ?
Do You need these features ?,
if You don't, a simple 3-Terminal-Regulator will work just fine.
.
.
.

 

Why are You using a Regulator with a bunch of extra features that You don't understand ?
Do You need these features ?,
if You don't, a simple 3-Terminal-Regulator will work just fine.

The obvious reason to use it is, the MP1495S is a switching regulator with higher efficiency than a linear regulator.

 

The obvious reason to use it is, the MP1495S is a switching regulator with higher efficiency than a linear regulator.

It is much easier to get it right the first time than it used to be, but you do have to read the datasheets and application notes with some care, or the firmament will rise up and smite thee.

 

It is much easier to get it right the first time than it used to be, but you do have to read the datasheets and application notes with some care, or the firmament will rise up and smite thee.

I already mentioned those application notes and the spec sheet in post #3. In addition to that, switcher regulators are a lot more critical relative to the arrangement of their connections, because they are more sensitive and also have a much higher frequency response.

 

It's a little confusing since it's shown as an I/O pin, but Vcc is the internal 5V bias voltage.
It's not an input, so no external voltage is applied.

Use the circuit as shown in the bottom right of your post.

Thank you very much!

You must read and understand the applications information, which describes the operation, not just the connections. The other connections are not all "external input ports."

I read it several time, its my first design, so there are some things that are not most clear to me.
Thanks you too.

 

the firmament will rise up and smite thee.

The cheesey poet once again surfaces for a breath of air

 

The cheesey poet once again surfaces for a breath of air

Actually that comes as a result of learning to fly

 

Actually that comes as a result of learning to fly

Philosophy and poetics are at the heart of the human condition. Unfortunately most never can or care to realize... Learning to "fly" is right!

 

Now that the wannabee poets are done, I am wondering how much current the TS wants the regulator to deliver, and is it at 5 volts. That is a guess, based on ????? Wit a switcher that uses external resistors the output voltage can be selected.

The Texas Instruments website has a lot of good information about exactly how to apply different switcher control chips, and that may be a very good place to look and learn. And possibly choose one of those that has the complete design and bill of materials and even a PCB layout. In addition they give good explanations as to why the parts are chosen.