i get output voltage sine wave with only 0.4 volt. can anyone explain me why this happens? and provide me a solution if it is possible

 

Hello,

What you are showing is just a block diagram.
There is no information at all about the control signals.

Bertus

 

Hi,

You had shown 3 scopes .Which scope is getting 0.4V .Please tell us.

 

Hi,

You had shown 3 scopes .Which scope is getting 0.4V .Please tell us.

scope which is connected after the transformer

 

Hello,

What you are showing is just a block diagram.
There is no information at all about the control signals.

Bertus

pulses for rectifier stage

 

pulses for push-pull inverter stage

 

Hello,

Those pictures do not say wich thyristors are switched when.
The thyristor signals should be synced with the input AC.
A time graph would sy much more.
Also on the output the signals should also alternate.
And again a timegraph will say much more.

Bertus

 

Hello,

Those pictures do not say wich thyristors are switched when.
The thyristor signals should be synced with the input AC.
A time graph would sy much more.
Also on the output the signals should also alternate.
And again a timegraph will say much more.

Bertus

actually output of the rectifier stage is perfect without connecting the inverter stage but when i connect inverter at the output of the rectifier graph becomes distorted. i will send you the graph if you want

 

Hi,
you are saying transformer at secondary side. If that you meant, the switching circuit is not functioning(oscillating).

See your Base signal if available and goes out to collector. You are using bipolar transistor not mosfet.

 

Hi,
you are saying transformer at secondary side. If that you meant, the switching circuit is not functioning(oscillating).

Hi,
you are saying transformer at secondary side. If that you meant, the switching circuit is not functioning(oscillating).

See your Base signal if available and goes out to collector. You are using bipolar transistor not mosfet.

i m using igbt, even if i m using mosfet i get the same output

 

You asked for an explanation (on your duplicated thread)..
So here is a quick one without going into details of how the CD4047 works.

The 12V battery is kept charged from mains via X1 transformer and bridge rectifier D1-D4. This 12V is fed to transformer X2 primary center tap.
When S2 is turned on, CD4047 is running as an oscillator alternately pulsing Q high, !Q low, turning T1 FET on, T2 FET off, switching current through top half of transformer X2. Next half cycle, CD4047 outputs Q1 goes low, !Q goes high, turning T1 FET off, T2 FET on, switching current through bottom half of transformer X2.
This AC at 12V is stepped up to 240V via the action of the transformer.

If you cannot understand this, I think you need to start with a much simpler project and learn some basics first.
Look at.. http://www.learnabout-electronics.org/
Also, there are some good guides on the EDUCATION link in this web site.

Please note! If you intend to make this UPS, it can be lethal !!