I have been told to build the following circuit and adjust the POTS so that the pulse generators produce a 2:1 mark to space ratio and a 6KHz output.
ok so i have managed to adjust the width to achieve that, however i now must adjust VR1 ( adjust graph height) so that that output is 5v. my question is why must the output be equal to 5V ?

thanks

 

VR1 does not adjust the output voltage. Did you mean VR2?

John

 

VR1 does not adjust the output voltage. Did you mean VR2?

John

Yes i apologise, VR2 adjusted to about 53% gives a 5v output, ,,, also the iput battery is 9v not 5v.

thanks

 

That makes sense now, because the 555 is not "rail-to-rail." That is, it can't drive its output completely to its supply levels.

As for your question of "why 5 V," I assume it must be feeding something downstream that needs just 5 volts, not 7 or 8 volts. A microcontroller would be an example of one such device.

John

 

That makes sense now, because the 555 is not "rail-to-rail." That is, it can't drive its output completely to its supply levels.

As for your question of "why 5 V," I assume it must be feeding something downstream that needs just 5 volts, not 7 or 8 volts. A microcontroller would be an example of one such device.

John

thanks for your help

 

I have been told to build the following circuit and adjust the POTS so that the pulse generators produce a 2:1 mark to space ratio and a 6KHz output.

The output is NOT variable, the output requires 2/3rd of the period to be high and 1/3rd to be low. The period remains constant (1/6 kHz). In your drawing, the frequency changes.

You might want to revisit your schematic.

Can you post a picture of the assignment's statement.

 

@JoeJester Check out Posts #2& #3. There was a misstatement in the original question.

John