Hi all,

My first post so here we go. My SN74HCT00 IC specs are VCC = 4.5 V to 5.5 V and input current of 1 µA Max

What would be the best way to regulate my 9v supply to meet these conditions? Voltage divider? Zener diodes?

Thanks in advance for any help

David

 

LM78L05

 

LM78L05

Hi Albert

Many thanks for your reply. Although it looks like the LM78L05 only supplies current in the mA range, which I believe is too high for my IC. But perhaps there is another differently rated power supply IC.

 

The LM78L05 will supply up to a maximum of 100mA. As long as you are drawing less than this then it will keep the voltage at a very stable 5V.

 

The LM78L05 will supply up to a maximum of 100mA. As long as you are drawing less than this then it will keep the voltage at a very stable 5V.

Thank you

 

LM78L05

That's one way - isn't there a 74xx pin compatible part with unbuffered CMOS specifications?

If so; it would be quite happy directly off a PP3 9V battery.

But if the HCT part is necessary, it wouldn't help much.

 

Does it have to be 74HCT00?
Use a CD4011 and it will run directly off a 9V battery.
Note that the pinout of CD4011 is not the same as 7400 NAND gate.

 

Thanks everyone for the advice.CD4011 will be fine. Looks like adding another IC is the way to go

Much appreciated