I understood what you said. .what I don't understand is, why add 240 V? Isn't Vs= Is/Zline?
L Thread Starter lisa3412 Joined Sep 6, 2014 37 Sep 14, 2014 #21 I understood what you said. .what I don't understand is, why add 240 V? Isn't Vs= Is/Zline?
t_n_k Joined Mar 6, 2009 5,455 Sep 14, 2014 #22 lisa3412 said: I understood what you said. .what I don't understand is, why add 240 V? Isn't Vs= Is/Zline? Click to expand... No. Firstly, voltage is current multiplied by impedance. The load end of the line is 240V. The linevoltage drop must be added to this to give the total source voltage.
lisa3412 said: I understood what you said. .what I don't understand is, why add 240 V? Isn't Vs= Is/Zline? Click to expand... No. Firstly, voltage is current multiplied by impedance. The load end of the line is 240V. The linevoltage drop must be added to this to give the total source voltage.
L Thread Starter lisa3412 Joined Sep 6, 2014 37 Sep 14, 2014 #24 Ok! thank you. So, is Vs= 285 @ angle 1.94 ?
t_n_k Joined Mar 6, 2009 5,455 Sep 14, 2014 #25 lisa3412 said: Ok! thank you. So, is Vs= 285 @ angle 1.94 ? Click to expand... That's close enough - I have it as 286.3 @ +1.95 degrees [Volts] Well done!
lisa3412 said: Ok! thank you. So, is Vs= 285 @ angle 1.94 ? Click to expand... That's close enough - I have it as 286.3 @ +1.95 degrees [Volts] Well done!
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