Hi, I am doing some studying but I'm very stuck.
My question is, I have a 30W, 200V, 800rpm dc motor connected to a 230V single phase, 50HZ line using a bridge converter. The full load armature current is 150A and the armature resistance is 0.06 Ohms.
I have worked out the firing angle under rated full load like this:
VRMS=230V
Vd=200V
So Vd/(0.9*VRMS) = 200/(0.9*230) = .96 ArcTan = 15 degrees.
The thing I'm stuck on is hoe to calculate the firing angle required so that the motor developes its rated torque at 400rpm.
Please could anyone help?
My question is, I have a 30W, 200V, 800rpm dc motor connected to a 230V single phase, 50HZ line using a bridge converter. The full load armature current is 150A and the armature resistance is 0.06 Ohms.
I have worked out the firing angle under rated full load like this:
VRMS=230V
Vd=200V
So Vd/(0.9*VRMS) = 200/(0.9*230) = .96 ArcTan = 15 degrees.
The thing I'm stuck on is hoe to calculate the firing angle required so that the motor developes its rated torque at 400rpm.
Please could anyone help?
