Please Help :(

Thread Starter

Girlzone

Joined Apr 5, 2004
1
Hi all,
i have a question, which ask to prove the identity of the following Boolean equation, using algebraic manipulation:

XZ + WY'Z' + W'YZ' + WX'Z' = XZ + WY'Z' + WXY' + W'XY + X'YZ'

i have tried many times to solve it but its very hard :wacko: , would please any one help me with it ..
Thanx a lot
 

m4yh3m

Joined Apr 28, 2004
186
I just joined here... but I figured I'd give a response anyways in case if others were curious.

Problem:
XZ+WY'Z'+W'YZ'+WX'Z'=XZ+WY'Z'+WXY'+W'XY+X'YZ'

Solution:
First, convert those ugly end of the alphabet letters to the more frequently used letters... A through H.
A=W
B=X
C=Y
D=Z

Our new problem looks like this:
BD+AC'D'+A'CD'+AB'D'=BD+AC'D'+ABC'+A'BC+B'CD'

Now simplify both sides to get:
A'CD'+AB'D'+AC'D'+BD=A'CD'+AB'D'+AC'D'+BD
 
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