Please can anyone find the gain for this circuit? i have uploaded the circuit and this is a link also : http://s000.tinyupload.com/?file_id=04863447381340379754

 

Please put the schematic in you post. I don't click on random links that might infect my computer.

Bob

 

Greetings
I do understand that u might be suspicious and worried about your pc there is plenty of trojans around so for that how do you recommend me to upload the figure you would like it on Dropbox or via email or whatsapp Image or any other method kindly note that is is an urgent issue and I would like to find the gain of this circuit

I attached the graph here if this is not enough or not a trustworhty issue let me know!
Thank you in advance
Ali

 

I'd say a Kirchhoff node analysis is the way to go here.
Apart from that, I'm not doing your homework for you.

 

so for that how do you recommend me to upload the figure you would like it on Dropbox or via email or whatsapp Image or any other method

Sarcastic is rude. Don't talk like that to someone you just met and asking for help.

 

Sarcastic is rude. Don't talk like that to someone you just met and asking for help.

You didn't ask for help. You asked someone to do the work for you.

 

Please upload your schematic using the "Upload" button.

Who would ever design a circuit like that....?

 

See

 

It looks like you have the correct, if we ignore mention of R4.

 

See
View attachment 109633

But that is not the original circuit. His non-inverting input is the output. Wouldn't it be the same voltage as the inverting input. Gain of 1.

 

But that is not the original circuit. His non-inverting input is the output. Wouldn't it be the same voltage as the inverting input. Gain of 1.

I am sorry/
See new file

 

I am sorry/
See new file
View attachment 109682
View attachment 109683

So ... no gain ???

 

Who would ever design a circuit like that....?

Strictly a classroom question without practical application?

 

Apparently you do not understand.
Gain = Vout / Vin = V (out) / 1V = x.
The question you have put wrong. Maximum transmission coefficients on the pseudo-resonance is 1 = 0db (at a frequency of 159Hz =1/(10k * 0.1u) / 2Pi. On the other frequencies ratio is less than 1. Carefully watch my pictures. I showed what is (analytically) transfer coefficient. I used complex number.

 

Apparently you do not understand.
Gain = Vout / Vin = V (out) / 1V = x.
The question you have put wrong. Maximum transmission coefficients on the pseudo-resonance is 1 = 0db (at a frequency of 159Hz =1/(10k * 0.1u) / 2Pi. On the other frequencies ratio is less than 1. Carefully watch my pictures. I showed what is (analytically) transfer coefficient. I used complex number.

Certainly something for me to learn here. Math aside .. the output is connected to the non-inverting input. Shouldn't that follow the inverting input for a no gain condition? Frequency characteristics of the op amp not considered in my thoughts, of course.
Given your formula, if we double the values of R3 and R4 we get a gain of -2. ??? It seems the output of the op amp would follow your math but the output of the circuit is not the output of the op amp.
(edited to add ...)
Or will the inverting input be at virtual ground and the output following that. Not no gain. no output???
Or a current output like a Howland Current Pump?

 

LTspice ==> Mag(Gain)=1 Phase=-180 ==> Gain=-1 (freq=159Hz)
A formula I recheck. It seems I made a mistake somewhere.