Concerning Phototransistors... is there an actual base current since light activates the base? The reason why I ask is that with standard transistors:
Ie = Ic + Ib. Is the collector current the same as emitter current or is there an actual flow of electrons through the optical base? Am I the only one confused by this?
Ie = Ic + Ib. Is the collector current the same as emitter current or is there an actual flow of electrons through the optical base? Am I the only one confused by this?
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