panic mode
- Joined Oct 10, 2011
- 5,185
you need to get some numbers first. looking at the circuit i am estimating current draw in the 100mA (0.1A).
at 12V that is equivalent to 100-120 Ohm load.
adding LC filter where
L=20mH, max 3A, 500mOhm
and C = 4.7uF it is easy to see that 1ms long -150V transient will not get diminished

increasing capacitor value by three orders of magnitude does help. At least it gets you into range where voltage regulator is surviving.

but that inductor and capacitor are rather bulky. simple diode would completely get rid of any harm due to negative transients. (and that is what inductive loads produce when you turn them off). and with a small capacitor it would not even register. This still would not solve sticky relay contacts (which is why you should have diodes also across relay contacts)

the problem however remains for positive transients (load dump). those are positive (so diode will not help) and worse - they have more energy (last much longer but not as steep). so for this adding LC like in second example would help. cheaper and more compact solution would be a crow bar (zener and large transistor or SCR or whatever).

btw low R of inductor is not going to change much. even if it 2-3 Ohm, at current of 100mA that is only voltage drop of 0.2-0.3V. so why not add a resistor... on purpose?
for example using diode, 10 Ohm 2W resistor and 470uF capacitor would mean there is a supply voltage drop of about 1.6V but your circuit would be happy and the positive transients would be absorbed a lot better. and you could put two such caps in parallel. of course using inductor instead of resistor is better. (inductors and capacitors are storage devices and losses are small).
and if your target platform does not have other devices that could dump the load, this would not even be an issue.

at 12V that is equivalent to 100-120 Ohm load.
adding LC filter where
L=20mH, max 3A, 500mOhm
and C = 4.7uF it is easy to see that 1ms long -150V transient will not get diminished

increasing capacitor value by three orders of magnitude does help. At least it gets you into range where voltage regulator is surviving.

but that inductor and capacitor are rather bulky. simple diode would completely get rid of any harm due to negative transients. (and that is what inductive loads produce when you turn them off). and with a small capacitor it would not even register. This still would not solve sticky relay contacts (which is why you should have diodes also across relay contacts)

the problem however remains for positive transients (load dump). those are positive (so diode will not help) and worse - they have more energy (last much longer but not as steep). so for this adding LC like in second example would help. cheaper and more compact solution would be a crow bar (zener and large transistor or SCR or whatever).

btw low R of inductor is not going to change much. even if it 2-3 Ohm, at current of 100mA that is only voltage drop of 0.2-0.3V. so why not add a resistor... on purpose?
for example using diode, 10 Ohm 2W resistor and 470uF capacitor would mean there is a supply voltage drop of about 1.6V but your circuit would be happy and the positive transients would be absorbed a lot better. and you could put two such caps in parallel. of course using inductor instead of resistor is better. (inductors and capacitors are storage devices and losses are small).
and if your target platform does not have other devices that could dump the load, this would not even be an issue.

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