It doesn't work that way. Using dBm means that you have a FIXED reference of 1 milliwatt. If the input was 12 dBm the device would probably be overloaded. The 14 dBm output is obtained with an input of 1 dBm. So 1 dBm plus a gain of 13 dB gets you 14 dBm. Got it?If an output of an ic is given 14dBm and it's gain is 13dB. So if an input of 12dBm is applied then what must be it's output ?
Okay thank you.It doesn't work that way. Using dBm means that you have a FIXED reference of 1 milliwatt. If the input was 12 dBm the device would probably be overloaded. The 14 dBm output is obtained with an input of 1 dBm. So 1 dBm plus a gain of 13 dB gets you 14 dBm. Got it?
A bit dramatic perhaps. Many amplifiers have overload protection, but your point is well takenHello,
When you want to drive an amplifier capable of 14 dBm output and a gain of 13 dB with 12 dBm input, you will likely blowup the amplifier.
If it not gets blowup, a lot of unwanted signal will be present on the output due to the non linearity of the amplifier.
Bertus
I am using hmc462lp5 which is an lna . In its data sheet the output power is given 14.5 dBm, 13dB gain and absolute maximum rating of input power which is 18dBm. With these values won't the ic get overloaded ?It doesn't work that way. Using dBm means that you have a FIXED reference of 1 milliwatt. If the input was 12 dBm the device would probably be overloaded. The 14 dBm output is obtained with an input of 1 dBm. So 1 dBm plus a gain of 13 dB gets you 14 dBm. Got it?
So why they have given absolute maximum rating of input power 18dBm ? Won't it gon way over the saturation point ?Hello,
Did you see the specs table?
View attachment 127671
With 12 dBm input and 13 dB gain you will get vey close to the IP3 point and go over the saturation point.
Bertus
18dBm on the input is probably where destruction begins.So why they have given absolute maximum rating of input power 18dBm ? Won't it gon way over the saturation point ?
I see. Thank you18dBm on the input is probably where destruction begins.