I've tried the question but the answer seems to doesnt agree with me .. so i think this has supernode..
(V214)/4 =v2/3 +v3/2 + v3/6 .....1
v2 6v+v3.......2
(V214)/4 =v2/3 +v3/2 + v3/6 .....1
v2 6v+v3.......2
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1.2 MB Views: 4
Sorry.. for the 1.2 mb stuff.. it's my first time posting sorry..so it is like the v2 refers to voltage at node 2 and v3 is at node 3 ... and its under the topic of nodal analysis with voltage source so supernode is exist...as supernode lies between two non reference node.. the 6 v is in sipernode..for circuit that hasca supernode the rule is to have a support equation which i stated as 2 equation which is KVL ..for the 1 equation is the KCL equation since its involving node.. so yeahDo you REALLY need a 1.2 MB file?
Me thinks perhaps not. Seems 16 kB works just fine:
View attachment 93531
Your equations have V2, v2, and v3. How are we supposed to know what those are referring to? Mind reading? Remote viewing?
Define your terms.
And how, pray tell, are we to know which node is node 2 and which node is node 3? Engineering is not about guessing!so it is like the v2 refers to voltage at node 2 and v3 is at node 3
Okay, but your support equation needs to be an equation. You don't have an equation, only an expression.... and its under the topic of nodal analysis with voltage source so supernode is exist...as supernode lies between two non reference node.. the 6 v is in sipernode..for circuit that hasca supernode the rule is to have a support equation which i stated as 2 equation which is KVL ..for the 1 equation is the KCL equation since its involving node.. so yeah
So v2 6v + v3 =0 ..And how, pray tell, are we to know which node is node 2 and which node is node 3? Engineering is not about guessing!
Okay, but your support equation needs to be an equation. You don't have an equation, only an expression.
Yes.So
So v2 6v + v3 =0 ..
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by Luke James
by Luke James