- Joined Sep 6, 2023
Im trying to solve this one, but without any luck. My approach is as follows:
I added my own currentflow, called Ix. Then I would just simply solve:
Ix - I2 - I1 = 0 (KCL)
5V - 4700*Ix - 2V - 1200*I2 = 0V (KVL)
2V - 1000*I1 + 1200*I2 (KVL)
Is this the correct approach? After solving this i get I2 = 1.357 mA and I1 =-0.525mA, while the answer model says 1.33mA and -0.555mA...