Hot R: What happens if we put a 47Ω resistor across a 9V battery? [9 X 9 ]/47=1.7 W into 1W R = hot. A SP is not the same as a battery as it has much more internal resistance. The ckt is dooing exactly what it is suposed to do, draw enough current from SP to keep output at 9V. I believe I have said all of this before.
I looked up 1N4148 ans see 200 mA, so should be OK for all diode positions.
I see another error; top of R2 should go to SP. While here will explain Day-Night. As light decreases, SP V falls as it still has a light load, R4, V now under 9V so SP is isolated from boost by D1. LEDs now running only on battery. When desired level of darkness , set by R3, is reached, U1 out switches from lo to high. D5 conducts, putting a high on U2-5 which is greater than 2.5V ref. so U2 out goes from lo to hi, shutting off U5, disconnecting battery. This is a verry confusing ckt to me also. I paused to take another look at why the 9V battery-- was a leftover from prev modification & is not needed; remove 9 v battery & tie loose end of R11 to U5-S
I looked up 1N4148 ans see 200 mA, so should be OK for all diode positions.
I see another error; top of R2 should go to SP. While here will explain Day-Night. As light decreases, SP V falls as it still has a light load, R4, V now under 9V so SP is isolated from boost by D1. LEDs now running only on battery. When desired level of darkness , set by R3, is reached, U1 out switches from lo to high. D5 conducts, putting a high on U2-5 which is greater than 2.5V ref. so U2 out goes from lo to hi, shutting off U5, disconnecting battery. This is a verry confusing ckt to me also. I paused to take another look at why the 9V battery-- was a leftover from prev modification & is not needed; remove 9 v battery & tie loose end of R11 to U5-S
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