I see, base on Post #194, it suppose to be 25% duty cycle at 750Hz. Unless I missed out some post on that.By my calculations, the duty cycle is 60.66% on at 2.36 kHz.
The formula is frequency = 1.44 / ((R1 + R2 + R2) * C).
I wasn't following the thread at that point, so I can't say. I can calculate some new values for R1, R2, and C1 if you like.I see, base on Post #194, it suppose to be 25% duty cycle at 750Hz. Unless I missed out some post on that.
It calculates to 705.88 Hz with a 66.67% duty cycle. C4 plays no part in the frequency or the duty cycle.Yes I am not sure either. Maybe when Bernard is online he can tell us that.
R1 and R2 to 10k ohms, C1 to 68nf and C4 to 10nf can set it to around 720hz right? I am not sure on duty cycle calculation.
Yes that should be good enough to try out first. Thanks again tracecom. And also for duty cycle, how do you calculate them?With R1 = 5600 and a 1N4148 in parallel, R2 = 18000, and C1 = .047 μF, the frequency calculates to 736.5 Hz and the duty cycle to 23.7%. Is that close enough?
Yes I am using 100 ohms cause there is no 95 ohms, but it was posted that value.95 ohms is not a standard value; are you using 91 ohms or 100 ohms or what?
Okay, I will add that to the schematic. Bernard should be here soon, and will settle the question about the 555 timing, and I will make whatever changes are required there, and elsewhere, and repost the design.Yes I am using 100 ohms cause there is no 95 ohms, but it was posted that value.
Hi good morning tracecom, it is 8:54PM Friday night here.Okay, I will add that to the schematic. Bernard should be here soon, and will settle the question about the 555 timing, and I will make whatever changes are required there, and elsewhere, and repost the design.
It's 6:34 am on Friday here; what time and day is it in Singapore?
To get a duty cycle of less than 50% requires a diode in parallel with R2; the diode's anode should be connected to pin 7 and the cathode to pins 6/2. Then, the formula is Duty Cycle = R1/(R1 + R2).Hi good morning tracecom, it is 8:54PM Friday night here.
Anyway I found the formula for duty cycle in this forum which is
Duty Cycle = (R1 + R2)/(R1 + 2R2)
after calculation I got 56.73% and not that you mentioned 23.7% just now. I am confuse again lol. Anyway never mind that first, I assembling the circuit now with what is in the schematic first.
Yeah, but don't forget that a camel is just a horse designed by committee.My boss once said that a "commettie" would pick a well laid out ckt. with, neatly drawn schematic...
Eat enough for me, too.555 timing got lost along the way, I should have picked up on it, but go back to post # 194, pg. 20. R2= 43k, R3= 130k, D1, & C = .01, all close to std values. Measured times .33 ms, & 1.33 ms total period = 751.8 Hz.
Have to go now to free dinner.
It helps me a lot to print a copy of the schematic, and then use a highlighter to mark each part and each wire as I put it in.Okay thanks tracecom, i am still assembling the circuit. it is so challenging for me to complete it. Anyway when I am done, i will post picture and hopefully you can check if I had done it wrongly. I think I will lol.