Hi,

Fist post, with a big question. I've pretty much got by without asking many questions so haven't needed to post before so hopefully someone can help me...

Basically I want to create a fuse box which will protect against any sort of power supply I plug into it. My intention is to use this box for high current work (~2A) but I want to ensure my voltage remains in the ~12V range to ensure I can't electrocute myself.

I have been looking at MOSFET transistors and drivers and am struggling to understand exactly how they work...

I found this: http://docs-asia.electrocomponents.com/webdocs/0d89/0900766b80d896fa.pdf

So at first glance this appears to be within my design criteria, (4.5V-16.5V and 2A peak). Only thing is I really am struggling to understand how MOSFET transistors work and how to wire up this thing. According to the diagram on the driver it looks like I need an N type MOSFET, is that right? Also I read that I should connect my circuit to the 'OUT' side (after the MOSFET transistor), if so where do I connect the +12V VCC? Does this go to ground? Thanks for any help in understanding this thing.

 

Over voltage protection circuits often use an SCR to short out the supply and blow a fuse. If you google overvoltage protection circuit you will see many of them. Have a read and come back if you have any questions.

 

This looks to be exactly what I need, thanks very much. Added bonus is it is quite a cheap solution too! Many thanks!