Hey,
I've got some POS-300 / POS -535 / POS-1025 VCO from Mini-Circuits with 10 dBm (or 8.5 dBm) power output. looking for a power amp and found PHA-202+
In datasheet mentioned "Medium power, 1W."
1W = 30 dBm = 20 Vpp into 50-ohm load

How it's possible to drive 20 Vpp while the DC supply voltage is only 11 V?
How much is the Max output power?

Thanks

 

The output circuit is tuned. That means you need to put in only a small proportion in, to get a large output. The power remains the same but there is a transformation of voltage and current.

 

Thanks a lot kaindub

 

Expanding on @kaindub’s answer…

In generally don’t concern yourself with voltage or current in a case like this but with their product: power, in W(atts). Aside from the inevitable losses that conversion incurs, you can always trade voltage and current so long as \(V \times A\) remains constant.

 

Hey,
I've got some POS-300 / POS -535 / POS-1025 VCO from Mini-Circuits with 10 dBm (or 8.5 dBm) power output. looking for a power amp and found PHA-202+
In datasheet mentioned "Medium power, 1W."
1W = 30 dBm = 20 Vpp into 50-ohm load

How it's possible to drive 20 Vpp while the DC supply voltage is only 11 V?
How much is the Max output power?

Thanks

View attachment 316978

For the power output, it is clearly stated as 30.4 dBm, which means 30.4 dB above one milliwatt.
So breaking that down in an approximation, consider that 20 dB is a 1:10 ratio, meaning 10 milliwatts, 6 dB=1:4
so 29 dB =10x 4 x3. So 29dBm=120milliwatts. so 30.4 dBm is close to 150 milliwatts. That is a quite high signal level for such a small device. And that is the output at very little gain compression.
The stated "1W" in the specification listing is the maximum it can deliver, running class "C", which will require a decent output network to produce a low harmonic content signal.