We all need to be mindful that giving complete answers is contrary to our policy.Hi,
I agree, it was a cautionary note only, that's why I did not delete any posts.
Mod
We all need to be mindful that giving complete answers is contrary to our policy.Hi,
I agree, it was a cautionary note only, that's why I did not delete any posts.
Mod
Fair enough.OK, there is no argument that it works, but I was trying for a schematic that looked as much like the original problem as possible.
Hi Papabravo!! thank you a lot for helping me with that circuit. I have another circuit right now that I thought I did it right, but I'm having some trouble getting the same answer as the manual version. Could you take a look plz?First use the pencil icon to draw all the wires like this:
View attachment 295518
Then use the resistor symbol to place the resistors. When you place a component on top of a wire it removes the short across the terminals of the component. When you grab a symbol to place, the Ctrl-R key combination will rotate the symbol and Ctrl-E will flip the symbol side-to-side.
View attachment 295520
Place a voltage source on the left-hand side using the letter V or select it from the components menu, which is between the diode symbol and the hand symbol. Also place the current source on the right-hand side.
View attachment 295523
Lastly you want to add a behavioral voltage source whose name in the component directory is "bv"
View attachment 295524
Once you get this far then we have to show you how to edit the values, construct a simulation command, and run it.



The simulation looks correct.the answer should be: V1=-3V, V2=4.5V and V3=-15V. any ideias?
Always ask if the answer makes sense. You say that the answers SHOULD be V1=-3V, V2=4.5V and V3=-15V. But have you checked to see whether those answers are consistent with the problem?but the answer should be: V1=-3V, V2=4.5V and V3=-15V. any ideias?
So using a current-controlled current source looks correct?The simulation looks correct.
What is it about them that appears to be incorrect?What is the basis for the answers, as they appear to be incorrect?
It appears that "your way of doing it" is NOT doing nodal analysis, as specified by the problem, but rather to through the problem as a simulator and hope that it gives you the answer.View attachment 296251
this is the problem, I need to find v1,v2 and v3 with nodal analysis. Here is my way of doing it
If I(R3) = -1.5 A, what should the voltage difference between V1 and V2 be, according to the problem schematic?View attachment 296252
when I run, it gives me this:
View attachment 296253
but the answer should be: V1=-3V, V2=4.5V and V3=-15V. any ideias?
Nope.So using a current-controlled current source looks correct?
Although it is assigned, resistor voltage polarity vs. current direction is not apparent in LTspice since it is not shown on the schematic resistor symbol.Do you know what the polarity rules are for device currents in the simulator?
