- Joined Jun 1, 2023
schoolwork is to find it manually using tension node, my teacher said we can check our answers in the software(if we know how to use it) since his slides don't have solutionsWhy do you need this information? It wouldn’t be schoolwork, would it? We need this information in order to help.
By "using tension node", I'm going to infer that you are to find the answer using what we normally call "node voltage" or "nodal" analysis.schoolwork is to find it manually using tension node, my teacher said we can check our answers in the software(if we know how to use it) since his slides don't have solutions
There are two problems with that:I think the "e" voltage-dependent voltage-source would likely be easier to use for that function.
I did that, and I put the ground point already. I'm stuck now in the dependent voltage sourceFirst use the pencil icon to draw all the wires like this:
View attachment 295518
Then use the resistor symbol to place the resistors. When you place a component on top of a wire it removes the short across the terminals of the component. When you grab a symbol to place, the Ctrl-R key combination will rotate the symbol and Ctrl-E will flip the symbol side-to-side.
View attachment 295520
Place a voltage source on the left-hand side using the letter V or select it from the components menu, which is between the diode symbol and the hand symbol. Also place the current source on the right-hand side.
View attachment 295523
Lastly you want to add a behavioral voltage source whose name in the component directory is "bv"
View attachment 295524
Once you get this far then we have to show you how to edit the values, construct a simulation command, and run it.
OK - very good. First, place a Net Name on the junction of R1, R2, and R3. There is an icon showing the letter "A" between the GROUND icon and the resistor icon. That is what you use for Net Names. Call it something like "Vx"
It is fairly clear that the homework is not to show a solution in LTspice, but to solve the problem. He did most of the work on his own and this is just a bit of guidance. He still has to be able to justify and verify the results. That is something the simulator won't help with. It is why on an exam you still have to "show your work". I believe the TS understands that and that is why I did not finish my answer in my first post on this thread.Hi,
This is a homework assignment, please no complete solutions.
I don't see why.The main E-source has 4 pins and requires a control voltage which in this context complicates the situation.
OK, there is no argument that it works, but I was trying for a schematic that looked as much like the original problem as possible.I don't see why.
The control voltage is the Vs voltage across the 2Ω resistor so the "e" control terminals are just connected across that resistor.
The only entry is then to give "e" a gain of 2.
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by Duane Benson
by Aaron Carman