I have an issue with a analogue signal.
This signal is a 5Vdc, it is an output from a PCB which is a source to many A/D PCB. its output is connected using wire of length around 3 meters to a breakout terminal. This point distributes the signal to other 4 places (A/D PCB) using long wire ( 10 meters) . the first stage of the A/D converter is a low-noise high-precision amplifier (TLE2027AID), the output of the A/D goes to a digital system which can be accessed using a software interface to read the digital value.
The issue I have is that when I inject 5 Volts at the source (before cabling), I read 5.1 VDC using the software, How is that possible to have more voltage than the input? capacitance effect is not there because it is DC.
Somebody can tell what could be the issue so I can do some more investigation?
Thanks
This signal is a 5Vdc, it is an output from a PCB which is a source to many A/D PCB. its output is connected using wire of length around 3 meters to a breakout terminal. This point distributes the signal to other 4 places (A/D PCB) using long wire ( 10 meters) . the first stage of the A/D converter is a low-noise high-precision amplifier (TLE2027AID), the output of the A/D goes to a digital system which can be accessed using a software interface to read the digital value.
The issue I have is that when I inject 5 Volts at the source (before cabling), I read 5.1 VDC using the software, How is that possible to have more voltage than the input? capacitance effect is not there because it is DC.
Somebody can tell what could be the issue so I can do some more investigation?
Thanks