Consider also another circuit with one 12 volt battery and two resistors in series, 2 ohms and 10 ohms. By definition the current in each will be the same. By ohms law the voltage on the 2 ohm resistor will be 2 volts and the voltage on the ten ohm resistor will be 10 volts. (Note that this also satisfies Kerchoves voltage law.) The power dissipated in the 2 ohm resistor will be two watts, and ten watts will be dissipated in the ten ohm resistor. And the battery will be delivering 12 watts.

 

Oops. You missed one more.
Second line is 4Ω, not 5Ω.

Yep -- actually meant it to be 5 Ω but forgot how to divide.

 

Yep -- actually meant it to be 5 Ω but forgot how to divide.

I am quite certain that you meant 4 Ω because you wanted to keep the current the same at 5A.

 

They say a picture is worth a 1,000 words, but you still need ohms law

I hope I got this right?

 

I am quite certain that you meant 4 Ω because you wanted to keep the current the same at 5A.

Yep, you're right. Forgot the point of the exercise when I went back and looked. Getting old.