I think the answer is yes, for example, a shunt inductor and a series capacitor would drive the load impedance that is located at the extreme circunference where the reflective coefficient is equal to one to the center of the smith chart.

 

A pure reactive load is not a "load". It dissipates no power.

 

A pure reactive load is not a "load". It dissipates no power.

I also thought of that, but somehow i could sketch that in the smith chart and still try to add components to get it in the center of the chart.

 

In theory and in simulators the answer is yes. In the real world it is more complicated because most reactances are not perfect.