Explain how the IRF520 transistor operates using basic voltage control to achieve switching.
Thanks for any help
Thanks for any help
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That's not sufficient if you want a switch as the op asked.IRF520 is a enhancement-mode MOSFET. So to turn-on the transistor the gate-to-source voltage must be greater than the threshold voltage (Vg(th) in datasheet).
...without the 1 kohm resistor, the irf520 would burn up...i tried it!Back to the original, posted circuit: With the Gate driven from the 555 output pin, with the 555 powered from 12Vdc, the IRF520 will turn on properly. However, its On resistance is horrible (>0.25Ω). There are much better NFETs available for this application.
Also, a mystery to me is why the 1K pull-up resistor from Gate to +12V is there? It is not needed, it just wastes power, and could create a runaway motor...
Obviously, as pin 7 is an oc pin.without the 1 kohm resistor, the irf520 would burn up...i t
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