Hi guys,
I have a question. The diagram below shows the inverting amplifier. The sine wave has a DC offset of about 10V. However the source connected to the non inverting terminal is a DC source which has a value of 1V. In this case does the concept of virtual ground still apply. As far as I can tell , all the current still flows through resistors R1, R2 and none into the input of the opamp. Can anyone tell me why even if I replace the non inverting terminal source with ground, the potential at the non inverting terminal is not close to zero?
I have a question. The diagram below shows the inverting amplifier. The sine wave has a DC offset of about 10V. However the source connected to the non inverting terminal is a DC source which has a value of 1V. In this case does the concept of virtual ground still apply. As far as I can tell , all the current still flows through resistors R1, R2 and none into the input of the opamp. Can anyone tell me why even if I replace the non inverting terminal source with ground, the potential at the non inverting terminal is not close to zero?
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