ideal transform

shteii01

Joined Feb 19, 2010
4,644
If you ASSUME that clockwise direction is positive. Then I2, which is in counter clockwise direction, is negative.

8(I1)+(-4j)[I1-(-I2)]+V1-100=0
8(I1)+(-4j)[I1+I2]+V1=100
8(I1)+(-4j)I1+(-4j)I2+V1=100
(8-4j)I1-4j(I2)+V1=100
 

WBahn

Joined Mar 31, 2012
29,979
Uhm... because the impedance of a capacitor is negative?

What is your reasoning for why you think it should be addition and not subtraction -- there are a couple of possible reasons for the misunderstanding.
 
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