There are numerous tables available on the net.

View attachment 196758

no i don't mean this
i mean if we have only the voltageof a transformer can't we know the current by some kind of a formula ?

 

no i don't mean this
i mean if we have only the voltageof a transformer can't we know the current by some kind of a formula ?

If you know the power you can calculate the current.

Power P = voltage V x current I

 

If you know the power you can calculate the current.

Power P = voltage V x current I

yes i know this
thank u so much

 

Ampacity of copper wire depends on application, winding- raceway etc.
The rating I have for transformer using #12g is ~13.5 amps.
If the Va is actually 75va then the winding should produce around 6v to be within range.
Or higher voltage with a reduced current, accordingly.
Max. .

 

n

Ampacity of copper wire depends on application, winding- raceway etc.
The rating I have for transformer using #12g is ~13.5 amps.
If the Va is actually 75va then the winding should produce around 6v to be within range.
Or higher voltage with a reduced current, accordingly.
Max. .

no it is 12v so the current is less
thanks a lot

 

You can also run up closer to the gauge rating and monitor the heat dissipation of the transformer, using a suitable primary fuse.
The danger point is always when you approach saturation of the core.
Max..

 

If your load is 24W and the voltage is 12V,

I = P / V = 24W / 12V = 2A