So the I3=(Vc+9-Vb)/1 ?You know what, none of your two solutions is correct. Why? Because you made the same error in your hand calculation and in LTspice. In simply words your "definition" of an I3 (and Vx voltage) current is wrong.
How can I3 be equal to I3 = (Vc - 9V) /1Ω?
Do you see the error?
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by Luke James