I was just going to say I thought you were using a negative trigger when you updated your post...I'm utilizing Alex_t recommendation in post 128.
Grounded pins 8,9,10,11 ... and added the transistor and led on post 168.
It works on my sim .... not on my breadboard.
Did you replace the low value resistor with a 10k on the transistor base?
There's a possibility that, with a 12V supply and only 100Ω (or less) effectively 'shorting' the Q output to ground, the IC was damaged. Static electricity is also a killer of CMOS circuits such as the 4013.
I got the new 4013 and ULN2004 in today and your circuit worked on my Breadboard, thank you. I used 100nF for all 4 circuit capacitors, because that is all I had.HI
I hope no one minds me jumping in here but I have suggestion..
Why not use a ULN2004 to drive the loads?
See attached...I've only shown the graphic for one of the lamp circuits but they would both be the same.
Hi...glad it worked out.Thank you guys for ALL your advice and input.
I got the new 4013 and ULN2004 in today and your circuit worked on my Breadboard, thank you. I used 100nF for all 4 circuit capacitors, because that is all I had.
I looked at the datasheet for the ULN2004. It appears to be limited to 500mA per output channel. Correct?
I do not see 500mA being a problem, just want to confirm.
I'd definitely use the transistor. Even if the chip could handle the current output that you want, it would warm up considerably, and the transistor is much better suited to dissipate that sort of power.So is the safe bet to go with the BD139 output, NOT the ULN2004?
@Alec_t ... Thank you for sticking with me!
@eetech00 ... I have ST Micro 2004 chip drivers. I looked on the datasheet offered through mouser and I did NOT see a 100% duty cycle specifications.
My ultimate circuit would have (2) 4013. Each output would need to trigger 1 relay (16mA), 1 LED (10mA) and one 3 Watt bulb (250mA). LED and Relay would share 1 output (26mA total). If I was to use the ULN2004, that would leave me with 3 Uln2004 outputs left and I need 4. Each with a max rating of 250mA for the bulbs and the chip can only handle 100-150mA each output. .... So if this was to work, I would have to have (2) 4013 and (2) 2004 and share 2004 outputs.
Now if I go with the BD139 per 4013 output. There will be more PCB Components, but I'll have 1.5A max per 4013 output, which is enough to handle the Bulb, LED and relay.
So is the safe bet to go with the BD139 output, NOT the ULN2004?
So the 4013 could NOT supply enough saturation to the BD139? That must be why the circuit in post #187 works. The 4013 output is driving a 2N3904 to drive Base current of the BD139. .. Cause the 4013 output to directly drive the an BD139 didn't work. Even though both of our SIMs said it would work, it didn'tFor a high current load, the base current for a BD139 would be more than the 4013 could provide directly, so you would need to drive the BD139 base with another transistor.
Thank you for the valuable infoHi
Just as an FYI.
I tested a ULN2003a (didn't have a 2004) with a continuous 15v@600mA load (300ma on two separate pins).
I used 5v to drive the inputs. I measured the chip temperature with a laser temp gun for about 30 minutes.
The temp averaged about 36 degrees C.
The chip was warm (close to hot) to the touch but didn't burn.
I don't think I'd load this chip with more current then this without a heat sink.
Acually...they do...Thank you for the valuable info
They make heat sinks for IC chips? ... I didn't know
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