Here is where I am stuck. The minimum current that needs to flow through Rs is limted by the minimum zener current which in this case is 0.2mA. If Is is smaller than this then the output would be unregulated. The maximum current is capped by the maximum power of the zener which can be calculated from PzM1 ( Izmax = PzM1/Vz = 1.5W / 9 V = 166.66mA). Now to calculate the Maximum value of Rs I would suppose that Vi would be maximum and Is would be minimum so : Rsmax = (Vimax - Vz)/Ismin = (20-9)/0,2mA = 55Kohm . Is this correct?Hi VT
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Why are you dividing 1.5 W by 9 V? What is the voltage across V_z1?Here is where I am stuck. The minimum current that needs to flow through Rs is limted by the minimum zener current which in this case is 0.2mA. If Is is smaller than this then the output would be unregulated. The maximum current is capped by the maximum power of the zener which can be calculated from PzM1 ( Izmax = PzM1/Vz = 1.5W / 9 V = 166.66mA). Now to calculate the Maximum value of Rs I would suppose that Vi would be maximum and Is would be minimum so : Rsmax = (Vimax - Vz)/Ismin = (20-9)/0,2mA = 55Kohm . Is this correct?
I just drew the equivelent of the two zeners in series giving me a 9 V 1.5W zener. PzMAX = 1.5 W . So IzMAX = PzMAX / Vz = 1.5W/9VWhy are you dividing 1.5 W by 9 V? What is the voltage across V_z1?
One of the nice things about most engineering problems is that the correctness of an answer can be determined by the answer itself.Rsmax = (Vimax - Vz)/Ismin = (20-9)/0,2mA = 55Kohm . Is this correct?
But the 1.5 W limit isn't a combined limit for both -- one zener has no awareness of the other one. Each one only knows how much heat IT is producing. So I give you a 3 V zener that has a max power dissipation of 1.5 W, how much current can flow through it without violating that spec? How much current can flow through a 6 V zener that has a max power dissipation of 1.5 W? What dictates the maximum allowable current when both are placed in series?I just drew the equivelent of the two zeners in series giving me a 9 V 1.5W zener. PzMAX = 1.5 W . So IzMAX = PzMAX / Vz = 1.5W/9V
yea Il would be capped to 0.2 mA . ( Is = (Vi - Vz)/Rs = 0.2mA ) . But the load needs to be able to pull 30 mA ( IL = Vz/RLmin = 9 / 300 = 30mA ). So this isnt correct .One of the nice things about most engineering problems is that the correctness of an answer can be determined by the answer itself.
So let's see what happens if you use a 55 kΩ resistor in that circuit.
What is the voltage across the load resistor if it is at the lowest possible value of 300 Ω?
Does that meet the purpose of the circuit?
Well yea I picked the smalled PzMAX . This way the smaller power zener will never exceed its maximum rating.But the 1.5 W limit isn't a combined limit for both -- one zener has no awareness of the other one. Each one only knows how much heat IT is producing. So I give you a 3 V zener that has a max power dissipation of 1.5 W, how much current can flow through it without violating that spec? How much current can flow through a 6 V zener that has a max power dissipation of 1.5 W? What dictates the maximum allowable current when both are placed in series?
Also ask yourself, is the power rating of the zeners likely to be what sets the MAXIMUM value of the Rs? If Rs is set at some value, would you expect the power in the zeners to go UP if the value of Rs was increased from there?
So if 166.66 mA (note -- engineering results are generally reported to three significant figures unless something dictates otherwise) is flowing through the two zeners, how much power is each one dissipating? Can more current flow through them without violating the max power rating of either of them? If so, then 166.6 mA (note that it gets rounded down because it was a max value, and 166.7 mA would violate it) is not the correct maximum current.Well yea I picked the smalled PzMAX . This way the smaller power zener will never exceed its maximum rating.