Somehow I had very tiny experience with emitter coupled logics, but happened that I developed the system using an ultrafast++ comparator, where I found a brilliant AD96687 integral circuit being even better that most shameless of my dreams, so I obtained few of it, etched the pcb, mounted and only then realized that outputs are not for use a CMOS levels but ESL bipolar signal and negative levels. Damn, too small letters in the datasheet warning that this is extra special product. (http://web.pa.msu.edu/people/edmunds/HAWC/Manuals/feb_ad96685_96687_comparator.pdf)
Okay, as I was too lazy to redo anything from very beginning, I just hanged in free place the one bjt level shift cascade (common base circuit), however I applied a 1 kOhm instead of 50 Ohm recomended in datasheet. Would it be OK if I have no need for 100% of speed??
Other moment I am not sure, I used only one output not both. As it is opened emitter, I feel one hanging free may not harm the IC. Is it so??
Third moment am unsure is the latch inputs. I need no latching so I set em to +5 Volt. In the application example yet them are set to the +2V and via the 50 Ohm. May I burn something inside in my manner?? In no CMOS or TTL the straight connection to Vcc may not do ANY harm. How it is here?
And now the problem itself: one input of operational amplifier (I mean comparator) are measure signal but other is reference voltage got from resistive divider (making by 1,5 kOhm and 1 kOhm the 1 Volt from 2,5 V stable source). Thus I was wondering why I have near 1,6V instead of 1V on that input util I realized the surplus voltage is created by IC. Cutting the connection between IC and my divider, divider part give 1V but on free hanging IC input stays 2V. So- my decision, somehow I have killed it. But I observed the most best praxes of antistatic (earhened soldering, hand chain, and pcb gnd in common conture, and I have had no any accident about input overloading. Why it burned? There is no meaning to solder it my last IC I have in the shelf before I havent understood what have been happened....
I would highly appreciate the any help in those all mess. Preliminary thanks. Your`s indeed, John.
Okay, as I was too lazy to redo anything from very beginning, I just hanged in free place the one bjt level shift cascade (common base circuit), however I applied a 1 kOhm instead of 50 Ohm recomended in datasheet. Would it be OK if I have no need for 100% of speed??
Other moment I am not sure, I used only one output not both. As it is opened emitter, I feel one hanging free may not harm the IC. Is it so??
Third moment am unsure is the latch inputs. I need no latching so I set em to +5 Volt. In the application example yet them are set to the +2V and via the 50 Ohm. May I burn something inside in my manner?? In no CMOS or TTL the straight connection to Vcc may not do ANY harm. How it is here?
And now the problem itself: one input of operational amplifier (I mean comparator) are measure signal but other is reference voltage got from resistive divider (making by 1,5 kOhm and 1 kOhm the 1 Volt from 2,5 V stable source). Thus I was wondering why I have near 1,6V instead of 1V on that input util I realized the surplus voltage is created by IC. Cutting the connection between IC and my divider, divider part give 1V but on free hanging IC input stays 2V. So- my decision, somehow I have killed it. But I observed the most best praxes of antistatic (earhened soldering, hand chain, and pcb gnd in common conture, and I have had no any accident about input overloading. Why it burned? There is no meaning to solder it my last IC I have in the shelf before I havent understood what have been happened....
I would highly appreciate the any help in those all mess. Preliminary thanks. Your`s indeed, John.
