DRV8313 motor driver chip does not function as expected - simple circuit!

Thread Starter

Elazar

Joined Oct 29, 2019
36
Hi All,

This is part of a very simple experimental circuit,
and somehow the DRV8313 motor driver chip does not function as expected,

when the circuit is powered on the DRV8313, motor_1, motor_2, motor_3 pins output the desired voltages, BUT once I connect any motor load, the chip turns off right away.
The datasheet states that it can handle up to 2.5A and the motor I have connected is less than 1.5A (for a very short amount of time)
Please see datasheet: https://www.ti.com/lit/ds/symlink/drv8313.pdf?ts=1618735338519

I don't see anything wrong with the circuit design.
DRV8313.png
The code that runs, is a simple test code to enable and test the chip

See the simple code below:

C:
#define EN3      8
#define IN3      9
#define EN2      10
#define IN2      11
#define EN1      12
#define IN1      13
#define NRESET   A0
#define NSLEEP   A1
#define FAULT    A2
#define RELAY_1  4
#define RELAY_2  5
#define RELAY_3  6


void setup() {
  pinMode(EN3,  OUTPUT);//EN3
  pinMode(IN3,  OUTPUT);//IN3
  pinMode(EN2, OUTPUT); //EN2
  pinMode(IN2, OUTPUT); //IN2
  pinMode(EN1, OUTPUT); //EN1
  pinMode(IN1, OUTPUT); //IN1
  pinMode(NRESET, OUTPUT);//NRESET
  pinMode(NSLEEP, OUTPUT);//NSLEEP
  pinMode(FAULT,  INPUT_PULLUP); //FAULT


  digitalWrite(NRESET, LOW);
  delay(100);
  digitalWrite(NRESET, HIGH);
  digitalWrite(NSLEEP, HIGH);
 
  digitalWrite(EN1, HIGH);
  digitalWrite(EN2, HIGH);
  digitalWrite(EN3, HIGH);
  digitalWrite(IN1, HIGH);
  digitalWrite(IN2, LOW);
  digitalWrite(IN3, LOW);

}

void loop() {
  delay(2000);
}
 

AlbertHall

Joined Jun 4, 2014
11,506
Your circuit is missing some capacitors recommended in the datasheet.
The motor will draw a lot more than that 1.5A at start up and that may be hitting the overcurrent protection in the chip.
 

Thread Starter

Elazar

Joined Oct 29, 2019
36
You are correct!

I have placed a 470uF capacitor on the VCC next to the chip and it started to work!

Thank You!
 
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