catalin_cluj
- Joined Nov 6, 2012
- 2
Apart from all the other mistakes, you can not use a peltier to heat to 100C.
It will melt/break at around 80C.
You need another solution.
It will melt/break at around 80C.
You need another solution.
Hi, Thanks crustchow. One doubt regarding your simulation. why you connecting the load terminal to gate of the mosfet?The L298 bridge will only carry 2A max.
The TEC12706 operates at up to 6A.
You could use a MOSFET bridge.
Below is the LTspice simulation of a simple bridge circuit that should work.
One input generates current in one direction through the TEC and the other input in the other direction.
The N and P MOSFETs can be any rated at ≥20V Vds and ≤25mΩ on-resistance.
The N-MOSFETs must be logic level type devices.
V2 and V3 are the Raspberry's outputs.
Note that you must make sure V2 and V3 are never on at the same time or you will short the bridge.
View attachment 130459
The L298 bridge will only carry 2A max.
The TEC12706 operates at up to 6A.
You could use a MOSFET bridge.
Below is the LTspice simulation of a simple bridge circuit that should work.
One input generates current in one direction through the TEC and the other input in the other direction.
The N and P MOSFETs can be any rated at ≥20V Vds and ≤25mΩ on-resistance.
The N-MOSFETs must be logic level type devices.
V2 and V3 are the Raspberry's outputs.
Note that you must make sure V2 and V3 are never on at the same time or you will short the bridge.
View attachment 130459
When one of the bottom N-MOSFETs is turned on, its drain voltage goes to ground.why you connecting the load terminal to gate of the mosfet?

You bridge has some fatal errors.
First, you need resistors in the base of all the transistors to limit the current.
Each base-emitter junction looks like a forward-biased diode with about 0.7V drop.
The resistors should be selected to limit the base current to about 1/10th of the collector current.
Second, the PNP top transistor on one side has to have a low base signal while the bottom NPN transistor on the other side has to have a high signal for the bridge to conduct proper current into the load.
The other PNP transistor must have a high base signal (6V) and the bottom NPN base must be grounded so they are off.
You can do that by driving both transistors on the same side (through their respective base resistors) from the same 0-6V signal.
But note that configuration will have some transistor feedthrough current when switching which my cross-coupled technique avoids.
It's not a breadboard fault. It's a breadboard-user faultIs this due to the breadboard fault
Ok cool. i don't think i am making mistake in the breadboard connection. That's y asked.It's not a breadboard fault. It's a breadboard-user fault.
Have you read post #21?
Why are you using a TEC for heating?
Use heating element.we are planning to heat one aluminium block which will be placing on top of the TEC12706.
Why? This TEC is not a best option?
I don't know.It will go till 80deg celsius know?
Its just a 6cm*5cm. Small block only. That's y we are going ahead with TECUse heating element.
I don't know.
How big is the aluminium block?
Because the circuit still not correct.Simulation is working but when I connected the same circuit in breadboard ,the voltage is not properly going across the peltier.

Why don't you try it and see what happens?Its just a 6cm*5cm. Small block only. That's y we are going ahead with TEC
Hey crustchow.Because the circuit still not correct.
You added base resistors for the bottom transistors, why not the top ones?
Also the saturation voltage of those transistors is about 2V each
View attachment 131151
so the voltage across the TEC will be about 4V less than the supply voltage.
Each ON transistor will thus dissipate about 6W @ 3A.
(You really should learn how to read data sheets).
I suggest you to use some appropriate MOSFETs instead.
They must be logic-level types.