Hello all, just a question regarding the input when a differential signal is passed to a matched differential amplifier.
\(V_{id} = V_{1} - V_{2}\) (1)
Then they describe V1 and V2 in terms of their differential and common-mode terms:
\(V_{1} = \frac{V_{id}}{2} + V_{ic}\) (2)
\(V_{2} = -\frac{V_{id}}{2} + V_{ic}\) (3)
I just don't understand how they determine that half of the differential signal will be sent to the bases of both transistors, with opposite polarities. I do understand how they got equation (1), but the half Vid is confusing me.
Thanks!
\(V_{id} = V_{1} - V_{2}\) (1)
Then they describe V1 and V2 in terms of their differential and common-mode terms:
\(V_{1} = \frac{V_{id}}{2} + V_{ic}\) (2)
\(V_{2} = -\frac{V_{id}}{2} + V_{ic}\) (3)
I just don't understand how they determine that half of the differential signal will be sent to the bases of both transistors, with opposite polarities. I do understand how they got equation (1), but the half Vid is confusing me.
Thanks!