Tell me please. I'm dealing with a differential amplifier. And he got confused.
I solve the examples and question 9 in the spoiler - the answer is there and the formula. I do not understand where it comes from.
Question 9
And Answer
How do I understand the operation of a differential amplifier with one input signal:
Transistor Q1 is an amplifier with a common emitter. The amplification of Rc / (re + RE || re). Since RE >> re, the gain is approximately A = Rc / 2re.
As I understand it, if Q2 is in a mode with a common base, then its input resistance is Z = re + RE || re.
And since A = Vout / Vin = (i * Rc) / (i * Z) => Rc / 2re.
I understand correctly?
I solve the examples and question 9 in the spoiler - the answer is there and the formula. I do not understand where it comes from.
Question 9
And Answer
How do I understand the operation of a differential amplifier with one input signal:
Transistor Q1 is an amplifier with a common emitter. The amplification of Rc / (re + RE || re). Since RE >> re, the gain is approximately A = Rc / 2re.
As I understand it, if Q2 is in a mode with a common base, then its input resistance is Z = re + RE || re.
And since A = Vout / Vin = (i * Rc) / (i * Z) => Rc / 2re.
I understand correctly?