Hello , I have a single ended PID and a vccs driver (differential )
What is the best way to connect the two, so the PID output will be driver input?
Thanks.
LTspice is attached.

 

Ground one of the differential inputs, and connect the other to the single-ended output.
Note that the differential circuit will amplify any DC offset from the single-ended signal.

 

Hello crutschow,maybe there is a" better" way like using some single ended to differential converter,like shown in the link?
The problem Is I need a component that will not ruin the behavior of single ended circuit.
What could be done? what do you reccomend?
Or should I stick to you suggestion of groundung one leg of the differential circuit and thats it?
Thanks.

 

maybe there is a" better" way like using some single ended to differential converter,like shown in the link?

I see no advantage to doing that for your circuit.
That converter is mainly needed if the input goes below 0V but the differential circuit input can't, which is not the case with your circuit.
The connection I suggested should work fine.

 

Hello crustshow, I tried to connect the two circuits as you said .
I get on the output of the PID circuit a very bad behavior as if te is not single below.
Where did I go wrong?
LTspice file is attached
Thanks.

 

It looks like the circuit is not powered since the gain is in the noise.
Where are the voltage sources for Vp and Vn?

 

Hello crutshow, Is it the connection you reccomended to use?
Thanks.

 

Is it the connection you reccomended to use?

Not quite.
U1 in your posted schematic is in integrator with no DC feedback for the input bias so it is saturating at the rail voltage.
Connect a 1megΩ resistor across C1 to provide the proper DC feedback bias.

 

Hello crutschow, I added the resistor you said and my integrator turns the pulse into a ramp.
But as you can see my differentiator is supposed to convert the pulse into two "deltas"/spikes
How should I improve the differentiation so it will convert the pulse into two spikes?(as shown in the photo)
Thanks.