How does that differentiate between the AC and the DC on the same lead?You just need to connect both left side of your circuit and the left side of my circuit to power supply line
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How does that differentiate between the AC and the DC on the same lead?You just need to connect both left side of your circuit and the left side of my circuit to power supply line
I would suggest adding a reverse connected 1N4148 across the LED in U1 To cope with the leakage in the 1N4004.Here's the circuit with two optos.
The Out_AC (yellow trace) is only high for the AC input, and the Out_AC_DC (green trace) is high for both AC and DC inputs.
I agree. Thank you.I would suggest adding a reverse connected 1N4148 across the LED in U1 To cope with the leakage in the 1N4004.
i was responding to Crutschow post about using BJTs as a current source on the AC side of the optocoupler.Which BJT and what voltage? The transistor in the coupler only needs to handle the 5V for the micro.