You just need to connect both left side of your circuit and the left side of my circuit to power supply line

How does that differentiate between the AC and the DC on the same lead?

 

Here's the circuit with two optos.
The Out_AC (yellow trace) is only high for the AC input, and the Out_AC_DC (green trace) is high for both AC and DC inputs.

 

At first glance, very nice, crutschow. Thank you! I'll digest it further tomorrow.

As you pointed out, the merging of the other 2 circuit wasn't going to work.

 

Here's the circuit with two optos.
The Out_AC (yellow trace) is only high for the AC input, and the Out_AC_DC (green trace) is high for both AC and DC inputs.

I would suggest adding a reverse connected 1N4148 across the LED in U1 To cope with the leakage in the 1N4004.

 

I would suggest adding a reverse connected 1N4148 across the LED in U1 To cope with the leakage in the 1N4004.

I agree. Thank you.

 

I doubt that the low reverse leakage current of a 1N004 will cause any degradation of the opto input LED, since the reverse current dissipation in the LED would be very low.
But adding the diode is fine.

 

Which BJT and what voltage? The transistor in the coupler only needs to handle the 5V for the micro.

i was responding to Crutschow post about using BJTs as a current source on the AC side of the optocoupler.
so in this case transistor Vce need to tolerate AC peaks plus some reserve. this is much higher than 5V that is on optocoupler output.