Initially, I tested my circuit assuming the AC power source (our lab uses a 5V amplitude AC source at 1kHz) has a 1ohm series resistance (in actuality its 50ohm). The basic setup is just

**AC source**-->

**Transformer**-->

**Full Bridge Rectifier**-->

**Smoothing capacitor**-->

**5V DC Output**

Below is the initial circuit and its voltage output. The green arrow corresponds with the green voltage waveform measured at that point, and blue with blue etc. R1 represents the load, and C1 is a smoothing capacitor. D1, D2, D3, D5 are 1N4001 diodes.

In order to work out the specific values of L1 and L2 (the turns ratio for the transformer), I just used an inductance ratio formula:

When I factor in the AC source resistance of 50ohms, as follows:

The waveforms (measured from the same points) look vastly different:

As you can see the voltages in both cases have been reduced drastically to the range of tens of milivolts. My question is if this is directly an effect of the AC source resistance being much higher, and if I can fix this by continuing to adjust the turns ratio.