I don't see a component where a value change would cause excessive power dissipation. A wiring error would do it, though.OP is making a mistake in one of the values given.
Maybe the light bulb is the wrong one and draws much more current than we think.I don't see a component where a value change would cause excessive power dissipation. A wiring error would do it, though.
Have you checked the polarity of D2? If it is backward, your transistor will get very hot if D2 survives.The D2 was present in the original circuit so I put it there as well to make it similar. I think its to dissipate any inductive or current spike when the circuit is first initiated.
can you tell me how did u come up R4 to be 18K?
When the darlington is linear so it is not saturated and has a voltage of 5V between its collector and emitter then its hFE (DC current gain) at 200mA is 10000.And finally can someone please tell me when the datasheet mentions
DC current gain hFE
(200mA, 5V) 10000
What does it mean and how it will effect my circuit.
I asked this before but i havent got a detailed explanation yet.
So if someone could help it will be great
Saturation is needed to keep the transistor cool, but I don't think that is the intention of the circuit. If it were, there would be no need for the RC filter or the emitter resistor.When the darlington is linear so it is not saturated and has a voltage of 5V between its collector and emitter then its hFE (DC current gain) at 200mA is 10000.
The datasheet also shows that it saturates fairly well with much more base current than above.
You want the darlington in your circuit to saturate. Then its hFE should be calculated to be no more than 500.
The same applies to ANY transistor. Look at the saturation spec of a 2N3904 in post #42. Its hFE is calculated to be only 10. But when the 2N3904 is not saturated so it has plenty of collector to emitter voltage then its hFE is from 100 to 300.
I can't find a spice model for MPSW13, apparently because it is obsolete.So you do see that it does get very hot. Can you try the same with MPSW13 and see if there is any difference. I don't know how to create new models on LTSpice.
Thank you very much!!!.
I respectfully submit that you don't have a clue.Samridh:
Q1 is working as a switch. So it will work in Saturation or cutoff region. The original design set the Q1 base never higher than few volts.
In your replacement, Q1 will be charged to 18V. And will never go to Saturation. So it's an amplifier and will burn. Fix your control ckt from R2 to the left.
Please refer to MPSW45 figure 9, 10 and MPSW13 figure 3,4.
Hee, hee. When I tell something like that to a NOOB then I am banned for a week. Maybe your word Respectfully might be the difference. Respect for a NOOB??I respectfully submit that you don't have a clue.![]()
Yeah, I was a little concerned... still am, for that matter. It just irks me when we have been chewing on a very complex problem (incandescent bulb hot vs cold resistance and thermal time constant, mainly) for a week, and a 2-poster comes in who probably has not read the entire thread and confidently makes statements that are wrong.Hee, hee. When I tell something like that to a NOOB then I am banned for a week. Maybe your word Respectfully might be the difference. Respect for a NOOB??
Most NOOBs don't have a clue.
There should be a special website for NOOBs.
And if the NOOB is from a foreign country then ...... never mind.
Y'all come down heah to see me some day, y'heah?The US is my neighbour. Most of us speeky zee same language but I have difficulty understanding a southern drawl, a hill-billies accent and some slang in New York.
I was right wasn't I ?OP's Theory and practical does not match ! Period
What frequency and duty cycle are you running now?Can someone still explain that why was capacitor causing transistor to blow up or resistor to smoke out when conencted to the main station!!!