Joined Jun 17, 2014
Got anxious about it and I don't know how to start solving this. Sorry for the bad drawing.View attachment 234070
Hey this is interesting. I assume that all the capacitors are of equal value?
With the right values for each capacitor and oriented correctly this can be taken as an elemental electrostatic space element in three dimensions.

But there are different ways to approach the problem at hand, so maybe you should mention what you have learned so far and provide your best attempt to solve it so we know.


Joined Aug 7, 2020
Try it with resistors - you can actually build it and measure it with a meter to prove whether you have got it right.


Joined Jan 6, 2004
I solved a resistor cube using delta wye conversions.

After that it was implemented in a protoboard and finally in LTSpice.


Joined Nov 13, 2010
You could use nodal analysis; there are only six nodes. It should be simple enough; all voltage drops across capacitor reactance instead of resistance (pick a frequency - any frequency).



Joined Aug 7, 2020
If you draw the cube, the connections are at A and D. A connects to three identical points B via an impedance, and D connects to three identical points C via an impedance.
Each B joins to two Cs via an impedance. Each C joins to two Bs. All impedances are equal.
So if you joined all three Bs together with a piece of wire, then no current would flow in the wire, as the voltage across its ends would be zero
Same for C.
Now does it look easier?