Got anxious about it and I don't know how to start solving this. Sorry for the bad drawing.

 

hi CinC,
Welcome to AAC.
As this is Homework please post your attempt at answering, we can then help.
E

 

Symmetry is the key.

 

Got anxious about it and I don't know how to start solving this. Sorry for the bad drawing.View attachment 234070

Hey this is interesting. I assume that all the capacitors are of equal value?
With the right values for each capacitor and oriented correctly this can be taken as an elemental electrostatic space element in three dimensions.

But there are different ways to approach the problem at hand, so maybe you should mention what you have learned so far and provide your best attempt to solve it so we know.

 

Try it with resistors - you can actually build it and measure it with a meter to prove whether you have got it right.

 

I solved a resistor cube using delta wye conversions.

After that it was implemented in a protoboard and finally in LTSpice.

 

You could use nodal analysis; there are only six nodes. It should be simple enough; all voltage drops across capacitor reactance instead of resistance (pick a frequency - any frequency).

 

If you draw the cube, the connections are at A and D. A connects to three identical points B via an impedance, and D connects to three identical points C via an impedance.
Each B joins to two Cs via an impedance. Each C joins to two Bs. All impedances are equal.
So if you joined all three Bs together with a piece of wire, then no current would flow in the wire, as the voltage across its ends would be zero
Same for C.
Now does it look easier?